function emailCheck (emailStr) { /* The following pattern is used to check if the entered e-mail address fits the user@domain format. It also is used to separate the username from the domain. */ var emailPat=/^(.+)@(.+)$/ /* The following string represents the pattern for matching all special characters. We don't want to allow special characters in the address. These characters include ( ) < > @ , ; : \ " . [ ] */ var specialChars="\\(\\)<>@,;:\\\\\\\"\\.\\[\\]" /* The following string represents the range of characters allowed in a username or domainname. It really states which chars aren't allowed. */ var validChars="\[^\\s" + specialChars + "\]" /* The following pattern represents the range of characters allowed as the first character in a valid username or domain. I just made it the same as above, but if you want to add a different constraint, you would change it here. */ var firstChars=validChars /* The following pattern applies if the "user" is a quoted string (in which case, there are no rules about which characters are allowed and which aren't; anything goes). E.g. "jiminy cricket"@disney.com is a legal e-mail address. */ var quotedUser="(\"[^\"]*\")" /* The following pattern applies for domains that are IP addresses, rather than symbolic names. E.g. joe@[123.124.233.4] is a legal e-mail address. NOTE: The square brackets are required. */ var ipDomainPat=/^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/ /* The following string represents at atom (basically a series of non-special characters.) */ var atom="(" + firstChars + validChars + "*" + ")" /* The following string represents one word in the typical username. For example, in john.doe@somewhere.com, john and doe are words. Basically, a word is either an atom or quoted string. */ var word="(" + atom + "|" + quotedUser + ")" // The following pattern describes the structure of the user var userPat=new RegExp("^" + word + "(\\." + word + ")*$") /* The following pattern describes the structure of a normal symbolic domain, as opposed to ipDomainPat, shown above. */ var domainPat=new RegExp("^" + atom + "(\\." + atom +")*$") /* Finally, let's start trying to figure out if the supplied address is valid. */ /* Begin with the course pattern to simply break up user@domain into different pieces that are easy to analyze. */ var matchArray=emailStr.match(emailPat) if (matchArray==null) { /* Too many/few @'s or something; basically, this address doesn't even fit the general mould of a valid e-mail address. */ alert("Email address seems incorrect (check @ and .'s)") return false } var user=matchArray[1] var domain=matchArray[2] // See if "user" is valid if (user.match(userPat)==null) { // user is not valid alert("The Email Address doesn't seem to be valid.") return false } /* if the e-mail address is at an IP address (as opposed to a symbolic host name) make sure the IP address is valid. */ var IPArray=domain.match(ipDomainPat) if (IPArray!=null) { // this is an IP address for (var i=1;i<=4;i++) { if (IPArray[i]>255) { alert("Destination IP address is invalid!") return false } } return true } // Domain is symbolic name var domainArray=domain.match(domainPat) if (domainArray==null) { alert("The domain name doesn't seem to be valid.") return false } /* domain name seems valid, but now make sure that it ends in a three-letter word (like com, edu, gov) or a two-letter word, representing country (uk, nl). If there's a country code at the end of the address, the full domain must include a hostname and category (e.g. host.co.uk or host.pub.nl). If it ends in a .com or something, make sure there's a hostname.*/ /* Now we need to break up the domain to get a count of how many atoms it consists of. */ var atomPat=new RegExp(atom,"g") var domArr=domain.match(atomPat) var len=domArr.length if (domArr[domArr.length-1].length<2 || domArr[domArr.length-1].length>3) { // the address must end in a two letter or three letter word. alert("The Email address must end in a three-letter domain, or two letter country.") return false } /* If it ends in a country code, we want to make sure there are at least 2 atoms preceding it (representing host and category (i.e. com, gov, etc.)) */ if (domArr[domArr.length-1].length==2 && len<3) { var errStr="This address ends in two characters, which is a country" errStr+=" code. Country codes must be preceded by " errStr+="a hostname and category (like com, co, pub, pu, etc.)" alert(errStr) return false } /* If it just ends in .com, .gov, etc., make sure there's a host name. This case can never actually happen because earlier checks take care of this implicitly, but we'll do it anyway. */ if (domArr[domArr.length-1].length==3 && len<2) { var errStr="This address is missing a hostname!" alert(errStr) return false } // If we've gotten this far, everything's valid! return true; }